X^2+3x-450=0

Solution for X^2+3x-450=0 equation:

X^2+3X-450=0

a = 1; b = 3; c = -450;
Δ = b2-4ac
Δ = 32-4·1·(-450)
Δ = 1809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1809}=\sqrt{9*201}=\sqrt{9}*\sqrt{201}=3\sqrt{201}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{201}}{2*1}=\frac{-3-3\sqrt{201}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{201}}{2*1}=\frac{-3+3\sqrt{201}}{2}
$